A stupid question

[seonewbee]

I would like to use php to generate a menu in table cells that will exclude the current page from the menu. I have heard that it is bad to have a page link to itself. Can this be done for a table that has 3 col and 3 rows? I want the menu to be at the top of the page. Would I need to have some tag with an id on each page so it knows which item to leave out?

Thanks in advance for all your assistance.

[imaginemn]

Try this. Here is a quick and easy sample.

[code:1:95e42c5493]<style>
.menudown { background-color: #498046;
font-family: Courier New;
padding: 3px;
border: inset #498046 2px;
margin-top: 2px;
color: #FFFFFF;
text-decoration: none
}

.menuup { background-color: #8CAE8A;
font-family: Courier New;
border: outset #8CAE8A 2px;
padding: 3px;
margin-top: 2px;
color: #006600;
text-decoration: none
}
.menuup:hover { background-color: #6C8E6A;
font-family: Courier New;
border: solid #FFFFFF 2px;
padding: 3px;
margin-top: 2px;
color: #FFFFFF;
text-decoration: none
}
</style>


<?php

//You need to define each page. You could also do this dynamically as a variable but this works for this example.
$pagenumber = 1;

for($i=1; $i<=10; $i++)
{
//If we are on page number $pagenumber
if($i == $pagenumber)
{
//We don't need a link so just print page's name.
echo '<span class="menudown">Link ' . $i . '</span>';
}
//We are not on page $pagenumber
else
{
//Print a link to page $i
echo '<a class="menuup" href="' . $i . '.php">Link ' . $i . '</a>';
}
}

?>

<P>Here is the rest of the HTML.</P>[/code:1:95e42c5493]

imaginemn